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glsl: remove unused state variable

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Because compile_shader function state variable
not determine whether the compilation is successful.

Signed-off-by: cheyang <cheyang@bytedance.com>
Reviewed-by: Tapani Pälli <tapani.palli@intel.com>
Part-of: <https://gitlab.freedesktop.org/mesa/mesa/-/merge_requests/8178>
This commit is contained in:
cheyang
2020-12-20 21:00:46 +08:00
committed by Marge Bot
parent 972e9ca294
commit ffe87c2689
1 changed files with 2 additions and 5 deletions
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7
src/compiler/glsl/standalone.cpp
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@@ -380,15 +380,12 @@ load_text_file(void *ctx, const char *file_name)
static void
compile_shader(struct gl_context *ctx, struct gl_shader *shader)
{
struct _mesa_glsl_parse_state *state =
new(shader) _mesa_glsl_parse_state(ctx, shader->Stage, shader);
_mesa_glsl_compile_shader(ctx, shader, options->dump_ast,
options->dump_hir, true);
/* Print out the resulting IR */
if (!state->error && options->dump_lir) {
_mesa_print_ir(stdout, shader->ir, state);
if (shader->CompileStatus == COMPILE_SUCCESS && options->dump_lir) {
_mesa_print_ir(stdout, shader->ir, NULL);
}
return;