util: Make DECLARE_LINEAR_ALLOC_* macros assume no destructors

Linear allocator doesn't support calling custom destructors to
its child allocations nor freeing individual child allocations.
So the destructor callback and the delete operator don't apply
to objects using linear allocator.

Reviewed-by: Marek Olšák <marek.olsak@amd.com>
Part-of: <https://gitlab.freedesktop.org/mesa/mesa/-/merge_requests/25280>
This commit is contained in:
Caio Oliveira
2023-09-18 01:15:42 -07:00
committed by Marge Bot
parent aec516ead6
commit b269cadf56

View File

@@ -517,7 +517,7 @@ void gc_sweep_end(gc_ctx *ctx);
*
* which is more idiomatic in C++ than calling ralloc.
*/
#define DECLARE_ALLOC_CXX_OPERATORS_TEMPLATE(TYPE, ALLOC_FUNC) \
#define DECLARE_RALLOC_CXX_OPERATORS_TEMPLATE(TYPE, ALLOC_FUNC) \
private: \
static void _ralloc_destructor(void *p) \
{ \
@@ -545,16 +545,27 @@ public: \
}
#define DECLARE_RALLOC_CXX_OPERATORS(type) \
DECLARE_ALLOC_CXX_OPERATORS_TEMPLATE(type, ralloc_size)
DECLARE_RALLOC_CXX_OPERATORS_TEMPLATE(type, ralloc_size)
#define DECLARE_RZALLOC_CXX_OPERATORS(type) \
DECLARE_ALLOC_CXX_OPERATORS_TEMPLATE(type, rzalloc_size)
DECLARE_RALLOC_CXX_OPERATORS_TEMPLATE(type, rzalloc_size)
#define DECLARE_LINEAR_ALLOC_CXX_OPERATORS_TEMPLATE(TYPE, ALLOC_FUNC) \
public: \
static void* operator new(size_t size, void *mem_ctx) \
{ \
void *p = ALLOC_FUNC(mem_ctx, size); \
assert(p != NULL); \
static_assert(HAS_TRIVIAL_DESTRUCTOR(TYPE)); \
return p; \
}
#define DECLARE_LINEAR_ALLOC_CXX_OPERATORS(type) \
DECLARE_ALLOC_CXX_OPERATORS_TEMPLATE(type, linear_alloc_child)
DECLARE_LINEAR_ALLOC_CXX_OPERATORS_TEMPLATE(type, linear_alloc_child)
#define DECLARE_LINEAR_ZALLOC_CXX_OPERATORS(type) \
DECLARE_ALLOC_CXX_OPERATORS_TEMPLATE(type, linear_zalloc_child)
DECLARE_LINEAR_ALLOC_CXX_OPERATORS_TEMPLATE(type, linear_zalloc_child)
/**
* Do a fast allocation from the linear buffer, also known as the child node