anv: Make entrypoint resolution take a gen_device_info
In order for things such as the ANV_CALL and the ifuncs to work, we used to have a singleton gen_device_info structure that got assigned the first time you create a device. Given that the driver will never be used simultaneously on two different generations of hardware, this was fairly safe to do. However, it has caused a few hickups and isn't, in general, a good plan. Now that the two primary reasons for this singleton are gone, we can get rid of it and make things quite a bit safer. Signed-off-by: Jason Ekstrand <jason@jlekstrand.net>
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@@ -214,22 +214,14 @@ for layer in [ "anv", "gen7", "gen75", "gen8", "gen9" ]:
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print "};\n"
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print """
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static struct gen_device_info dispatch_devinfo;
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void
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anv_set_dispatch_devinfo(const struct gen_device_info *devinfo)
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{
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dispatch_devinfo = *devinfo;
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}
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static void * __attribute__ ((noinline))
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anv_resolve_entrypoint(uint32_t index)
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anv_resolve_entrypoint(const struct gen_device_info *devinfo, uint32_t index)
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{
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if (dispatch_devinfo.gen == 0) {
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if (devinfo == NULL) {
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return anv_layer.entrypoints[index];
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}
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switch (dispatch_devinfo.gen) {
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switch (devinfo->gen) {
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case 9:
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if (gen9_layer.entrypoints[index])
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return gen9_layer.entrypoints[index];
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@@ -239,7 +231,7 @@ anv_resolve_entrypoint(uint32_t index)
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return gen8_layer.entrypoints[index];
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/* fall through */
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case 7:
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if (dispatch_devinfo.is_haswell && gen75_layer.entrypoints[index])
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if (devinfo->is_haswell && gen75_layer.entrypoints[index])
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return gen75_layer.entrypoints[index];
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if (gen7_layer.entrypoints[index])
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@@ -301,7 +293,7 @@ print "};"
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print """
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void *
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anv_lookup_entrypoint(const char *name)
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anv_lookup_entrypoint(const struct gen_device_info *devinfo, const char *name)
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{
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static const uint32_t prime_factor = %d;
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static const uint32_t prime_step = %d;
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@@ -325,6 +317,6 @@ anv_lookup_entrypoint(const char *name)
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if (strcmp(name, strings + e->name) != 0)
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return NULL;
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return anv_resolve_entrypoint(i);
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return anv_resolve_entrypoint(devinfo, i);
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}
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""" % (prime_factor, prime_step, hash_mask)
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