intel/perf: don't generate logically dead code
When divisor is constant integer != 0 there's no point in checking whether it's 0. Complained about by Coverity. Signed-off-by: Marcin Ślusarz <marcin.slusarz@intel.com> Reviewed-by: Lionel Landwerlin <lionel.g.landwerlin@intel.com> Part-of: <https://gitlab.freedesktop.org/mesa/mesa/-/merge_requests/6126>
This commit is contained in:

committed by
Marge Bot

parent
0789f4b6d8
commit
289cb6b59a
@@ -105,7 +105,11 @@ def emit_uadd(tmp_id, args):
|
||||
def emit_udiv(tmp_id, args):
|
||||
c("uint64_t tmp{0} = {1};".format(tmp_id, args[1]))
|
||||
c("uint64_t tmp{0} = {1};".format(tmp_id + 1, args[0]))
|
||||
c("uint64_t tmp{0} = tmp{1} ? tmp{2} / tmp{1} : 0;".format(tmp_id + 2, tmp_id + 1, tmp_id))
|
||||
if args[0].isdigit():
|
||||
assert int(args[0]) > 0
|
||||
c("uint64_t tmp{0} = tmp{2} / tmp{1};".format(tmp_id + 2, tmp_id + 1, tmp_id))
|
||||
else:
|
||||
c("uint64_t tmp{0} = tmp{1} ? tmp{2} / tmp{1} : 0;".format(tmp_id + 2, tmp_id + 1, tmp_id))
|
||||
return tmp_id + 3
|
||||
|
||||
def emit_umul(tmp_id, args):
|
||||
|
Reference in New Issue
Block a user